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Elections in Vermont |
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The 1846 Vermont gubernatorial election took place on September 1, 1846, [1] and resulted in the election of Whig Party candidate Horace Eaton to a one-year term as governor. [2]
In the race for governor, incumbent lieutenant governor Horace Eaton defeated Smith, a former member of the United States House of Representatives and Brainerd, a former member of the Vermont House of Representatives. [3]
In the popular vote for lieutenant governor, Whig Leonard Sargeant defeated Democrat Truman B. Ransom and Free Soil candidate Jacob Scott. [3] The vote totals were: Sargeant, 23,335 (47.4%); Ransom, 17,985 (36.6%); Scott, 7,801 (15.9%); scattering, 65 (0.1%). [3]
The contest for state treasurer resulted in the election of Whig Elisha P. Jewett, who defeated Democrat Daniel Baldwin and Free Soil nominee Zenas Wood. [3] Vote totals in the treasurer's race were: Jewett, 23,324 (48.2%); Baldwin, 17,847 (36.9%); Wood, 6,978 (14.4%); scattering, 192 (0.5%). [3]
Because none of the popular vote winners achieved the 50 percent required by the Constitution of Vermont, the Vermont General Assembly was required to choose the winners. [3] In most cases, the assembly selects the candidate who received a plurality of the vote. [3] In the October 8, 1846 legislative elections, Eaton, Sargeant, and Jewett all won their contests. [3] The reported vote totals were: [3]
Necessary for a choice: 111
Results:
Necessary for a choice: 112
Results:
Necessary for a choice: 111
Results:
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Whig | Horace Eaton | 23,644 | 48.5% | + 1.4% | |
Democratic | John Smith | 17,877 | 36.7% | - 1.8% | |
Free Soil | Lawrence Brainerd | 7,118 | 14.6% | - 1.1% | |
Scattering | 64 | 0.02% | - 0.05% | ||
Total votes | '48,703' | '100' | – |