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a minor point: "no two points (x,t) in X x I equivalent" is not correct if f is not injective. Thus we need a reformulation of the equivalence relation. -
Saibot2 16:19, 6 February 2007 (UTC)reply
![{\displaystyle ([t,x],s)\mapsto [(1-s)\cdot t,x],(y,s)\mapsto y}](https://wikimedia.org/api/rest_v1/media/math/render/svg/e19db21f4313b24498024b757773bd901c05501f)