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With an alternative construction, you take a
cuboctahedron, cut all the edges, and alternate vertices, you can twist the 6 square and 8 triangular faces until gaps remain that can be filled by pairs of triangles, like shown in these images (swapping blue and yellow triangle colors in the second image):
Tom Ruen (
talk)
04:46, 23 August 2009 (UTC)reply
Coordinates
I'm having trouble getting
to come out to 1.14261...
The numerical values seem correct (they give a snub cube with unit length edges),
so I suspect there may be a typo in the formula somewhere. Can anybody spot it? - IP71.127.175.197, 15:29, April 25, 2011
The same goes for edge length α.
doesn't give α = 1.60972.
I found another formula which does give the correct α:
I don't know if this is the official foruma (I'm sure it isn't). I got it by solving for α in α6-4α4+16α2-32=0, extracting out common factors equal to β and simplifying the rest by hand. I'm putting this in the article.
I can't find an easy replacement for C3, so I'm just going to leave that for the moment and use 1/ξ/α as the value. --
Zom-B (
talk)
17:52, 23 May 2011 (UTC)reply
Names for the chiral versions
"Left" and "right" versions on the respective side, duals in opposite cornersRed:left-facing swastika Yellow: right-facing
triskelion
Whether to use "red-based" or "yellow-based" names is a random choice, and I expect that both conventions exist. The more important question is if duals have the same or opposite directions.
Watchduck (
quack)
20:40, 26 July 2018 (UTC)reply
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