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Jakopovac Latitude and Longitude:

46°01′28″N 16°46′20″E / 46.0244343°N 16.7722427°E / 46.0244343; 16.7722427
From Wikipedia, the free encyclopedia
Jakopovac
Village
Jakopovac is located in Croatia
Jakopovac
Jakopovac
Coordinates: 46°01′28″N 16°46′20″E / 46.0244343°N 16.7722427°E / 46.0244343; 16.7722427
Country  Croatia
County Bjelovar-Bilogora County
Municipality Zrinski Topolovac
Area
 • Total1.7 sq mi (4.4 km2)
Population
 (2021) [2]
 • Total98
 • Density58/sq mi (22/km2)
Time zone UTC+1 ( CET)
 • Summer ( DST) UTC+2 ( CEST)

Jakopovac is a village in Croatia.

Demographics

According to the 2021 census, its population was 98. [2]

References

  1. ^ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata  Q119585703.
  2. ^ a b "Population by Age and Sex, by Settlements" (xlsx). Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.