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Doubles
2006 Queen's Club Championships
Final
Champions
Runners-up
Score6–4, 3–6, [10–8]
Details
Draw24
Events
Singles Doubles
←  2005 · Queen's Club Championships ·  2007 →
Main article: 2006 Stella Artois Championships

Bob Bryan and Mike Bryan were the defending champions, but lost in the semifinals this year.

Paul Hanley and Kevin Ullyett won in the final 6–4, 3–6, [10–8], against Jonas Björkman and Max Mirnyi.

Seeds

All seeds receive a bye into the second round.

  1. United States Bob Bryan / United States Mike Bryan (semifinals)
  2. Sweden Jonas Björkman / Belarus Max Mirnyi (final)
  3. The Bahamas Mark Knowles / Canada Daniel Nestor (semifinals)
  4. Australia Paul Hanley / Zimbabwe Kevin Ullyett (champions)
  5. Australia Stephen Huss / South Africa Wesley Moodie (second round)
  6. Czech Republic František Čermák / Czech Republic Leoš Friedl (quarterfinals)
  7. Zimbabwe Wayne Black / South Africa Jeff Coetzee (quarterfinals)
  8. Australia Wayne Arthurs / United States Justin Gimelstob (quarterfinals)

Draw

Key

Finals

Semifinals Final
          
1
5 64  
4
7 77  
4
6 3 [10]
2
4 6 [8]
3
77 64 [7]
2
65 77 [10]

Top half

First round Second round Quarterfinals Semifinals
1
77 6  
 
6 3 [10]  
60 4  
 
3 6 [6] 1
65 78 [10]
 
4 6 [10] 8
77 66 [7]
 
6 3 [2]  
     
8
w/o    
1
5 64  
4
7 77  
4
3 7 [10]
 
78 6    
6 5 [6]
 
66 3   4
6 6  
 
4 77 [11] 7
4 2  
 
6 61 [9]  
6r    
7
5    

Bottom half

First round Second round Quarterfinals Semifinals
6
w/o    
 
3 62    
     
 
6 77   6
5 4  
 
3 6 [9] 3
7 6  
 
6 2 [11]  
77 66 [11]
3
64 78 [13]
3
77 64 [7]
2
65 77 [10]
5
4 65  
 
5 65   WC
6 77  
WC
7 77   WC
64 2  
 
3 63   2
77 6  
WC
6 77   WC
77 4 [6]
2
64 6 77

External links

Retrieved from " https://en.wikipedia.org/?title=2006_Stella_Artois_Championships_–_Doubles&oldid=1177930010"