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The 1998 United States Virgin Islands gubernatorial election was held on 3 November 1998, in order to elect the Governor of the United States Virgin Islands. Democratic nominee Charles Wesley Turnbull defeated incumbent Republican Governor Roy Schneider. [1]
General election
On election day, 3 November 1998, Democratic nominee Charles Wesley Turnbull won the election by a margin of 5,804 votes against his opponent Republican Governor Roy Schneider, thereby gaining Democratic control over the office of Governor. Turnbull was sworn in as the 6th Governor of the United States Virgin Islands on 4 January 1999. [2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Charles Wesley Turnbull | 19,138 | 58.94% | |
| Republican | Roy Schneider | 13,334 | 41.06% | |
| Total votes | 32,472 | 100.00% | ||
| Democratic gain from Republican | ||||
References
- ^ "Gov. Charles W. Turnbull". National Governors Association. Retrieved 11 December 2023.
- ^ "USVI Governor". ourcampaigns.com. 19 January 2006. Retrieved 11 December 2023.
Categories:
- 1998 United States Virgin Islands elections
- 1998 United States gubernatorial elections
- 1998 in the United States Virgin Islands
- 1990s United States Virgin Islands elections
- 1990s in the United States Virgin Islands
- November 1998 events
- November 1998 events in North America
- November 1998 events in the United States
- 1998 elections
- 1998 elections in North America
- 1998 elections in the Caribbean
- 1998 elections in the United States
- Government of the United States Virgin Islands