1892_United_States_House_of_Representatives_election_in

1892 United States House of Representatives election in Wyoming

← 1890

November 8, 1892 (1892-11-08)

1894 →


Nominee	Henry A. Coffeen	Clarence D. Clark
Party	Democratic	Republican
Popular vote	8,855	8,394
Percentage	51.34%	48.66%

County results
Coffeen:      50–60%      60–70%
Clark:      50–60%
     No Data

U.S. Representative before election

Clarence D. Clark
Republican

Elected U.S. Representative

Henry A. Coffeen
Democratic

The Wyoming United States House election for 1892 was held on November 3, 1892. Democratic Henry A. Coffeen defeated Republican incumbent Clarence D. Clark with 51.34% of the vote making Clark the first incumbent Representative from Wyoming to lose reelection.

Results

United States House of Representatives election in Wyoming, 1892^[1]
Party		Candidate	Votes	%
	Democratic	Henry A. Coffeen	8,855	51.34%
	Republican	Clarence D. Clark (inc.)	8,394	48.66%
Total votes			17,249	100%

References

^ "United States House of Representatives election in Wyoming, 1892".

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