1860_United_States_presidential_election_in_Michigan References

1860 United States presidential election in Michigan
Lincoln 50-60% 60-70% 70-80%	Douglas 50-60% 60-70% 70-80%
President before election; James Buchanan; Democratic	Elected President ; Abraham Lincoln; Republican

The 1860 United States presidential election in Michigan took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.^[1]

Michigan was won by the Republican nominee, Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine. They defeated the Democratic nominee, Senator Stephen A. Douglas of Illinois and his running mate with 41st Governor of Georgia Herschel V. Johnson.^[1] Lincoln won the state by a margin of 15.24%.

The 1860 presidential election in Michigan began a trend in which the state would vote the same as Pennsylvania, as the two states would vote in lockstep with each other on all but three occasions since Lincoln’s victory - 1932, 1940, and 1976.

Results

1860 United States presidential election in Michigan^[1]
Party		Candidate	Votes	%
	Republican	Abraham Lincoln	88,450	57.23%
	Democratic	Stephen A. Douglas	64,889	41.99%
	Southern Democratic	John C. Breckinridge	805	0.52%
	Constitutional Union	John Bell	405	0.26%
Total votes			154,549	100%

References

^ ^a ^b ^c "1860 Presidential Election Results Michigan".

[source-1] "1860 Presidential Election Results Michigan".

[1]

Results

See also

References