From Wikipedia, the free encyclopedia
1860 United States presidential election in Iowa|
|
|
County Results
Lincoln
40-50%
50-60%
60-70%
70-80%
80-90%
90-100%
|
Douglas
40-50%
50-60%
60-70%
70-80%
80-90%
|
Tie
~50%
| |
|
The 1860 United States presidential election in Iowa took place on November 6, 1860, as part of the
1860 United States presidential election. Iowa voters chose four representatives, or electors, to the
Electoral College, who voted for
president and
vice president.
Iowa was won by the
Republican nominees
Illinois
Representative
Abraham Lincoln and his running mate
Senator
Hannibal Hamlin of
Maine. They defeated the
Democratic nominees
Senator
Stephen A. Douglas of Illinois and his running mate
41st Governor of Georgia
Herschel V. Johnson. Lincoln won the state by a margin of 11.39%.
Results
See also
References