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Election in Rhode Island
1840 United States presidential election in Rhode Island|
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The 1840 United States presidential election in Rhode Island took place between October 30 and December 2, 1840, as part of the
1840 United States presidential election. Voters chose four representatives, or electors to the
Electoral College, who voted for
President and
Vice President.
Rhode Island voted for the
Whig candidate,
William Henry Harrison, over
Democratic candidate
Martin Van Buren. Harrison won Rhode Island by a margin of 22.93%.
With 61.22% of the popular vote, Rhode Island would be Harrison's third strongest state in the 1840 election after
Kentucky and
Vermont.
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Results
See also
References